Physics, asked by roshu736, 1 year ago

equal volumes of two immiscible liquids of densities p and 2p are filled in a vessel. two small holes are drilled at depths h/2 and 3h/2 from the surface of the lighter liquid. if v1 and v2 are the speed of efflux at these two holes, then (v2/v1) is

Answers

Answered by techtro
21

The two immiscible liquids for the densities are р and 2p.

The two small holes are drilled at depth h/2 and 3h/2

So the speed vessels v1 = √2g (h/2) = √gh

According the from Bernoulli's Therom, At the same level of point we have to consider from one hole to other point as per the therom.

phg+2pg(h/2) = 1/2(2p)v₂²

v₂ = √2gh

v₁/v₂ = 1/√2

Therefore the speed of the holes (v₂/v₁) = 2:1

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