Question

Equal volumes of two solutions pH=2 and pH=4 are mixed together.

Calculate the pH of the resulting solution?

Answer 1

✔️let x be the vol. of both sol.

M1V1 +M2V2=Mnet Vnet

10-2 X x +10-4 X x= Mnet 2x

x(10-2 + 10-4) =Mnet 2x

10-2+10-4/2 = Mnet

Mnet= 5.05 X 10-3

✔️✔️now take -log on both sides..

pH=2.2967

➖➖➖➖or ➖➖➖➖

[Alternatively]


✔️✔️[H+] for solution with pH = 2 is 10-2 M

✔️✔️[H+] for solution with pH = 4 is 10-4 M

equal volumes of the given solutions are mixed; concentration will be halved.......

Therefore,

[H+] =10-2 +10-42         

=10-2 (1+10-2)2         

=1.01 x 10-22         

=0.505 x 10-2 M

pH = -log[H+]       

= -log (0.505 x 10-2)       

=2.29

Answer 2

H+] for solution with pH = 2 is 10-2 M
[H+] for solution with pH = 4 is 10-4 M


since, volumes are equal ,,

let x be the volume of both solutions

10-2 X x +10-4 X x= Mnet 2x

x(10-2 + 10-4) =Mnet 2x

10-2+10-4/2 = Mnet

Mnet= 5.05 X 10-3

now taking -log

answer ;- 2.2967

pH=2.2967

$thanks \: me \: later$


❤️❤️❤️