Question

Equal weights of He and CH4 gases are taken in a closed container. Fraction of total pressure exerted by He in container is how much..?

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Answer 1

Answer:

Taking the mole of hydrogen which is $\frac{x}{2}$

Taking the mole of methane which is $\frac{x}{16}$

The mole fraction of hydrogen and methane ia derived as $\frac{\frac{x}{2}}{\frac{x}{2}+\frac{x}{16}}$

That it is defined as the “partial pressure of hydrogen” divided by the total pressure and hence the answer is $\frac{8}{9}$.

The mole fraction of hydrogen is $\frac{8}{9}$.

To calculate the ‘mole fraction’ of methane in the similar approach thereby  

The mole fraction is now we have to calculate the fraction of total pressure exerted by methane is $\frac{1}{9}$