Question

equation for this
information .find the fare for travelling a distance or 4k
(ii) In Fig. AB||CD . find the value of x
CD130-
201​

Answer 1

From E, draw EF || AB || CD. EF || CD and CE is the transversal.

∴∠DCE+∠CEF=180o        [∵ Co-interior angles]

⇒xo+∠CEF=180o⇒∠CEF=(180−xo)

Again, EF || AB and AE is the transversal.

∠BAE+∠AEF=180o      [∵ Co-interior angles]

⇒105o+∠AEC+∠CEF=180o

⇒105o+25o+(180o−xo)=180o

⇒310−xo=180o

Hence, x=130o

Answer 2

ANSWER

Since, the lines are parallel

∠OCD=∠OAB

∠ODC=∠OBA

and

∠DOC=∠AOB (Vertically Opposite Angle)

Hence, △OCD∼△OBA

3x−1=5x−3⇒2x=2⇒x=1