Question

if A + B = 90° , then sin^2A + sin^2B =
A ) 1
B ) 0
C ) 1/2
D ) root 3 / 2

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Answer 1

Answer:

1

Explanation

A + B = 90

therefore B= 90 - A

so,

let, here A =a and B = b

$= {\sin }^{2} (a) + { \ { \sin}^{2} (b) }$

$= { \ { \sin }^{2} (a) } + { \ { \sin}^{2} (90 - a) }$

we know that,

sin (90 - a) = cos a

therefore,

$= { \sin(a) }^{2} + { \cos(a) }^{2}$

we know that sin^2 a + cos^2 a=1

$= 1$

Answer 2

Answer:

the above answer is correct