Equation for time of flight
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i know some equation
To find the time of flight, determine the time the projectile takes to reach maximum height. The time of flight is just double the maximum-height time.Start with the equation:vy = voy + ay tAt maximum height, vy = 0.The time to reach maximum height is t1/2 = - voy / ayTime of flight is t = 2t1/2 = - 2voy / ayPlugging in voy = vo sin(q) and ay = -g, gives:Time of flight is t = 2 vo sin(q) / gwhere g = 9.8 m/s2The time of flight is also determined solely by the initial velocity in the y direction and the acceleration due to gravity.
To find the time of flight, determine the time the projectile takes to reach maximum height. The time of flight is just double the maximum-height time.Start with the equation:vy = voy + ay tAt maximum height, vy = 0.The time to reach maximum height is t1/2 = - voy / ayTime of flight is t = 2t1/2 = - 2voy / ayPlugging in voy = vo sin(q) and ay = -g, gives:Time of flight is t = 2 vo sin(q) / gwhere g = 9.8 m/s2The time of flight is also determined solely by the initial velocity in the y direction and the acceleration due to gravity.
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I suppose it is a question in kinematics and forces, acceleration due to gravity, projectile motion.
If a particle is thrown in to the air at a projection angle Ф, with an initial speed u, it flies to a highest point and then returns to surface of earth at some distance.
Then the time for the particle to reach the highest point = u sin Ф / g
where g is acceleration due to gravity. we use v = u - g t and resolution of velocity vector along the vertical direction to solve this.
Time taken for the particle to touch ground from the highest point = u sin Ф / g
Time of flight = 2 u sin Ф / g
If the particle is thrown vertically upwards, the n duration of flight = 2u/g as Ф=90 degrees
If a particle is thrown in to the air at a projection angle Ф, with an initial speed u, it flies to a highest point and then returns to surface of earth at some distance.
Then the time for the particle to reach the highest point = u sin Ф / g
where g is acceleration due to gravity. we use v = u - g t and resolution of velocity vector along the vertical direction to solve this.
Time taken for the particle to touch ground from the highest point = u sin Ф / g
Time of flight = 2 u sin Ф / g
If the particle is thrown vertically upwards, the n duration of flight = 2u/g as Ф=90 degrees
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