Question

Equation of chord of a parabola y^2= 6x which is bisected at (-1,1)

Answer 1

Answer:

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Answer 2

Step-by-step explanation:

Here (x₁,y₁) = (-1,1)

Equation of chord T = S₁

T = y(1) - 3(x - 1)

  = y - 3x + 3

 = -3x + y - 3

Then:

S₁ = (1)² - 6(-1)

    = 1 + 6

 

    = 7

so,

-3x + y - 3 = 7

-3x + y - 4 = 0

y - 3x = 4

Hope it helps!