Question

equation of the circle with centre on the y-axis and passing through the origin and (2,3)is​

Answer 1

Step-by-step explanation:

We have to find equation of a circle with center on the y-axis.

General equation of such circle is

(x−0)

2

+(y−k)

2

=k

2

It passes through (2,3)

i.e, 2

2

+(3−k)

2

=k

2

⇒4+9+k

2

−6k=k

2

⇒k=

6

13

∴ Equation of circle =x

2

+(y−

6

13

)

2

=(

6

13

)

2

=6x

2

+6y

2

−13y=0