Equation of the circle with radius 3 and centre as the point of intersection of the lines
2x + 3y =5, 2x+y =l is
(A) x² +7=9
(B) x2+y2–2x–2y—7=0
(C) x2+x2–2x+2y+7=0
die
(D) x2 + y2 + 9 = 0
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Answer:
(C).......................
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