Math, asked by shaurya6467, 1 year ago

Equation of the plane passing through the line and point (4,3,7) is

Answers

Answered by MarkAsBrainliest
6
Answer :

We know that equation of any plane passing through the point (a1, b1, c1) is

A (x - a1) + B (y - b1) + C (z - c1) = 0,

where A, B, C are normal vectors to the plane.

In this problem the point is (4, 3, 7).

Hence, the required plane is

A (x - 4) + B (y - 3) + C (z - 7) = 0,

where A, B and C are normal vectors to the plane

⇒ Ax + By + Cz = 4A + 3B + 7C

#MarkAsBrainliest
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