Equation of three lines a,b and c in the following graph are
x y=0,x-y=0 and y=2( may not be written in an order).
match the given equation with lines a,b and c. also, find the area enclosed between these lines.
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see diagram. fig 1:
is the first straightline : x * y = 0 ?
x * y = 0 is same as , x = 0 and y = 0. So it is the x axis and the y axis.
x - y = 0 is same as x = y. the bisector of x and y axes in the 1st quadrant.
y =2 is the horizontal line.
The area enclosed is a right angle triangle : the colored area
= 1/2 * 2 * 2 = 2.
===========================
see diagram 2:
Is the first line : x + y = 0 ? then it is the bisector of - x and +y axes in the 2nd quadrant.
x - y = 0 and y = 2 are same like in the above.
The area enclosed by the three lines is colored. It is an isosceles triangle.
The area enclosed in the 1st quadrant is = 1/2 * 2 * 2 = 2.
Area enclosed in 2nd quadrant = same as in 1st quadrant = 2.
total area enclosed = 4 units.
is the first straightline : x * y = 0 ?
x * y = 0 is same as , x = 0 and y = 0. So it is the x axis and the y axis.
x - y = 0 is same as x = y. the bisector of x and y axes in the 1st quadrant.
y =2 is the horizontal line.
The area enclosed is a right angle triangle : the colored area
= 1/2 * 2 * 2 = 2.
===========================
see diagram 2:
Is the first line : x + y = 0 ? then it is the bisector of - x and +y axes in the 2nd quadrant.
x - y = 0 and y = 2 are same like in the above.
The area enclosed by the three lines is colored. It is an isosceles triangle.
The area enclosed in the 1st quadrant is = 1/2 * 2 * 2 = 2.
Area enclosed in 2nd quadrant = same as in 1st quadrant = 2.
total area enclosed = 4 units.
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