Question

equation of (x+1)2-x2 =0 has number of real root equal to
a. 1
b.2
c. 3
d.4 ​

Answer 1

This is ☝️ one degree eqn , hence here only one real root is possible
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Answer 2

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{x+1}²-x²

0=x²+2x+1-x²

0= 2x+1

-1/2= x

real root is 1 as it is linear equations