Question

Equation (x+1)2-x2=0 has how many real roots

Answer 1

Answer:

one answer

Step-by-step explanation:

to open a bracket of (x+1)² we square the first+twice their product+square the last

so (x+1)²= x²+2x+1

so (x+1)²-7x-4=0

is equal to x²+2x+1-x²=0; 2x+1=0

2x=-1

x=-1/2