Question

Equations of circles which
touch both the axes and
whose centres are at a
distance of 2v2 units from
origin are​

Answer 1

Answer:

please full question ok

Answer 2

Answer:

Correct option is

A

x2+y2±4x±4y+4=0

Since h=k (radius )

h2+k2=22

h2+k2=8

2h2=8     (Taking circle 1st Quad)

h=2 

∴k=2 in 

∴ center =(2,2)

Eqn. of circle having centre 

(h,k) & radius =r

(x−h)2+(y−k)2=r2

∴(x−2)2+(y−2)2=4