Equi convex lens is placed such that optic axis coincides with the x-axis, position of object is (−40cm,1cm) and position of image (50cm,−2cm) where is the lens located
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hey mate here is your answer
From the y coordinates of the position of object and image we use that the magnification
m=−2cm1cm=−2
image is real and inverted.
∴|u|=x
|v|=2x
Distance between object and image is
50−(−40)=90
∴x+2x=90
3x=90
x=30
distance of object from lens is 30 cm from lens.
∴ Distance of lens from origin is −10cm
Object is on other side with 60 cm from lens.
hope it helps you dear..
From the y coordinates of the position of object and image we use that the magnification
m=−2cm1cm=−2
image is real and inverted.
∴|u|=x
|v|=2x
Distance between object and image is
50−(−40)=90
∴x+2x=90
3x=90
x=30
distance of object from lens is 30 cm from lens.
∴ Distance of lens from origin is −10cm
Object is on other side with 60 cm from lens.
hope it helps you dear..
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