Equibalent mass of K₂Cr₂O₇ in acidic solution is
a) molecular mass/2
b) molecular mass/4
c) molecular mass/1
d) molecular mass/6
Answers
Answered by
0
⇒2×Mass of hydrogen+Mass of sulphur+4×Mass of oxygen
Here , Mass of one hydrogen atom =1u.
Mass of one sulphur atom =32u.
Mass of one oxygen atom =16u.
We get , Mass of one molecule of H2SO4
⇒2×1+32+4×16
⇒2+32+64
⇒98u
Here , Mass of one hydrogen atom =1u.
Mass of one sulphur atom =32u.
Mass of one oxygen atom =16u.
We get , Mass of one molecule of H2SO4
⇒2×1+32+4×16
⇒2+32+64
⇒98u
Answered by
1
In acidic medium
K2cr2o7 + 14H+ + 6e- →2k+ + 2 cr3+ + 7h20
By this equivalent weight of k2cr2o7 = 294.2/6 = 49.033
@skb
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