Question

Decomposition of 2 moles of NHNO at 100°C
NH₄NO₃ (s) → N₂O (g) +2H₂O₃ (g)

Calculate the work done in above reaction . State whether work is done on or by the system.

Answer 1

Dear Student,

◆ Answer -

Work = -18.6 kJ

Work is done on the system.

● Explaination -

In given reaction, two moles of NH₄NO₃ are involved -

2 × [NH₄NO₃(s) → N₂O(g) + 2 H₂O₃(g)]

In the reaction, change in no of moles is -

∆n = moles of products - moles of reactants

∆n = (4 + 2) - 0

∆n = 6

Work done is calculated by -

W = -RT∆n

W = -8.314 × 373 × 6

W = -18606 J

W = -18.606 kJ

Therefore, 18.6 kJ of work is done on the system.

Thanks dear...

Answer 2

Explanation:

it is a decomposition reaction..

since NH4NO3 decomposes into N2O and 2H2O