Question

Equilibrium concentration of 2 HI, I and 2 H is 0.7, 0.1 and 0.1M respectively. The equilibrium constant for the reaction 2 2 I + H ⇌ 2HI is (a) 36 (b) 49 (c) 0.49 (d) 0.36

Answer 1

Answer:

K=49

Explanation:

K=[HI]^2/[H2]×[I2]

K=0.7×0.7/0.1×0.1

K=49