Question

equilibrium , the concentrations of N2 O2 and No in sealed vessel at 800 K are : N2 = 3.0x10-3 M, O2 = 4.2x 10-3 and No 2.8x 10-3 M , Calculate the equilibrium constant Kc for the reaction N2 + O2 <=> 2NO. ​

Answer 1

Answer: Here's your answer!!!

Explanation: The reaction is N2+O2<====>2NO

The Kc will be [NO]^2/[N2] [O2]

[NO]=2.8*10^(-3)M

[N2]=3*10^(-3) M

[O2]=4.2*10^(-3)M

Hence Kc={2.8*10^(-3)}^2/{3*10^(-3)} {4.2*10^(-3)}

On solving we get Kc=7.84/3*4.2

Kc=0.6222

Hope it helps!!!!