equition of the line PQ is 3x+2y-5=0 write the slope of the line PQ.
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Answered by
3
We know that slope of line ax+by+c=0 is -a/b=-3/2
mysticd:
It is also correct but need explaination
Answered by
9
Given equation is ....
3x+2y-5=0
3x+2y = 5
2y = -3x + 5
y = -3x/2 +5/2. -------------(1)
on coparing equation (1) with
y = MX + c
where M= slope..
M= -3/2
so slope of given equation = - 3/2 ans.
3x+2y-5=0
3x+2y = 5
2y = -3x + 5
y = -3x/2 +5/2. -------------(1)
on coparing equation (1) with
y = MX + c
where M= slope..
M= -3/2
so slope of given equation = - 3/2 ans.
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