Equivalent mass of trivalent metal elements is 9eq,-1the molar mass of its anhydrous oxide
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For a trivalent metal n-factor = 3
Molar mass of the metal = equivalent mass x n-factor
= 9 x 3
= 27 grams
Therefore the molar mass of its anhydrous oxide is 27 grams
Molar mass of the metal = equivalent mass x n-factor
= 9 x 3
= 27 grams
Therefore the molar mass of its anhydrous oxide is 27 grams
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