Question

Equivalent volume of Co2, in the following reaction
will be
NaCO3 + HCI —NaCl + H2O + CO2
(1) 2.24 L
(3) 44.8L
(4) 5.6 L
(2) 11.2L​

Answer 1

Answer:

11.2 L.

Explanation:

Since, from the equation we get that each of the substance in the reactant and the product side are present in a quantity of 1 mole each. So, the equivalent volume of the CO2 can be calculated by using the formulae of standard volume / the n-factor of the CO2.

So, on substituting the values we will get that 22.4/2 = 11.2 L. Where the n-factor of the CO2 is 2 and the volume is known as the standard volume which is 22.4 L.