Equivalent weight of As2O3 in As2O3+2I2+2H2O--->As2O5+4HI
Answers
Answer:
Answer is 123.01g/equivalent
Explanation:
This is a redox reaction , so in order to determine the equivalent weight in this type or reactions, we have to follow this equations:
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where; O.A is an oxidizing agent and R.A is a reducing agent.
First, we can obtain the molecular weight of Arsenic sulfide from the Periodic Table of elements which is 246.02g/mol .
Second, we have to follow the change in oxidation number of As before the reaction and after it to determine the valency.
-As a reactant , the oxidation number of As in As2S3 is (+3)
-As a product , the oxidation number of As in (AsO4)-3 is (+5)
Hence, the change in oxidation number is 2 which is the absolute difference between them.
By substitution in the equation, the equivalent weight of As2S3 is 123.01g/equivalent .
Answer:
Equivalent weight of As2O3 in the given reaction is 49.5
Explanation:
Oxidation state per As atom in As2O3 is 6/2 = +3
Oxidation state per As atom in As2O5 is 10/2 = +5
Therefore the change in oxidation state for 1 As atom is +2
Therefore the change in oxidation state for 2 As atoms (since there are 2 atoms of arsenic in As2O3) is 2 x 2 = +4
So a net change in oxidation state of +4 has taken place in the reaction.
This change in oxidation state is also commonly called the n factor.
Therefore the n factor of As2O3 in this reaction is 4
Now, the molecular weight of As2O3 = (2 x 75) + (3 x 16) = 198
Equivalent Weight= (Molecular Weight / n factor) = 198 / 4 = 49.5