Equivalent weight of Fe2S3 in the reaction
Fe2S3+5O2=2FeSO4+SO2
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Molecular weight of Fe₂S₃ = 55.845 x 2 + 32.065 x 3
= 207.9 g
In Fe₂S₃ the oxidation state of S is -2.
In FeS0₄ the oxidation state of S is +6
In SO₂ the oxidation state of S is +4.
n factor = Total number of electrons lost or gained from each.
= 2 x 3 + 2 x 6 + 1 x 4
= 22
Equivalent weight = molecular weight / n factor
= 207.9 / 22
= 9.45 g
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