Question

Equivalent weight of KMnO4 in acidic medium

Answer 1

$\huge\mathbb{\blue{QUESTION-}}$

Equivalent weight of KMnO4 in acidic medium.

$\huge\mathbb{\blue{SOLUTION-}}$

$\large{\sf MnO_4^- + 8H^+ → Mn^{+2} + 4H_2O}$

${\sf here\:Mn^{+7} \: reduced \: to \: Mn^{+2} }$

⛬ n - factor of the reaction is '5'

Equivalent Weight ⎯

$\large{\boxed{\sf Equivalent\: Weight=\dfrac{Molecular \: Weight}{n-factor} }}$

Molecular Weight of ${\sf KMnO_4}$ is 158g

⛬ Equivalent Weight = ${\sf \dfrac{158}{5}}$

$\implies{\bf \red{Equivalent\: Weight=31.6} }$

$\huge\mathbb{\blue {ANSWER-}}$

Equivalent Weight of ${\sf KMnO_4}$ is ${\sf \red{31.5\:g}}$