Question

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Ratio of lenght and breadth of a rectangle is 3:2. If the length of rectangle is 5 m men
than the breadth find the perimeter of the rectangle​

Answer 1

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Answer 2

Correct Question

Ratio of lenght and breadth of a rectangle is 3:2. If the length of rectangle is 5 m greater than the breadth find the perimeter of the rectangle.

Answer

» As we know that the length of the rectangle is 5 metres greater than the breadth, we can also represent that in the form of ratio.

Breadth of the rectangle :

${\sf \leadsto x + 5 : x = 3 : 2}$

${\sf \leadsto \dfrac{x + 5}{x} = \dfrac{3}{2}}$

${\sf \leadsto 2 (x + 5) = 3x}$

${\sf \leadsto 2x + 10 = 3x}$

${\sf \leadsto 2x - 3x = 0 - 10}$

${\sf \leadsto -1x = -10}$

${\sf \leadsto x = \dfrac{-10}{-1} = 10}$

Now, let's find the length of the rectangle.

Length of the rectangle :

${\sf \leadsto x + 5 = 10 + 5}$

${\sf \leadsto 15}$

Now, we can find the perimeter.

Perimeter of the rectangle :

${\sf \leadsto 2 ( Length + Breadth)}$

${\sf \leadsto 2 (15 + 10)}$

${\sf \leadsto 30 + 20}$

${\sf \leadsto 50 \: metres}$

Hence, the Perimetre of the rectangle is 50 metres.