Question

erated of 1.5 metre per second square in a box .calculate the mass of the box.

Answer 1

Answer:

u=20ms

−1

v=0

f=μmgcosθ

u=20ms

−1

v=0

f=μmgcosθ

mgsinθ+f=ma

mgsinθ+μmgcosθ=ma

5

30

+0.5×10×

5

4

=a

6+4=a

a=10ms

−2

v

2

−u

2

=2as

0−20

2

=2×(−10)×s

s=20m

mgsinθ+f=ma

mgsinθ+μmgcosθ=ma

5

30

+0.5×10×

5

4

=a

6+4=a

a=10ms

−2

v

2

−u

2

=2as

0−20

2

=2×(−10)×s

s=20m