Question

es001-1.jpg : 7^2 x 7^8 / 7^4 = 7a/ 7^4 = 7^b

A = 10 B= 6

Answer 1

Hii There!!!

=> Refer the above attachment

Answer 2

Answer:

Using exponent rules:

• $a^m \times a^n = a^{m+n}$

• $a^m = a^n$ ⇒ m =n

Given the equation:

$\frac{7^2 \times 7^8}{7^4} = \frac{7^a}{7^4}=7^b$

We have to find a and b.

$\frac{7^2 \times 7^8}{7^4} = \frac{7^a}{7^4}$

⇒$7^2 \times 7^8 = 7^a$

Apply exponent rules:

⇒$7^{2+8} = 7^a$

⇒$7^{10}=7^a$

Apply exponent rules;'

⇒ a= 10

Similarly for:

$\frac{7^2 \times 7^8}{7^4} = 7^b$

$7^2 \times 7^8 = 7^b \times 7^4$

Apply exponent rules:

⇒$7^{10} =7^{b+4}$

Apply exponent rules;

$10 = b+4$

Subtract 4 from both sides we have;

$6 = b$

or

b = 6

Therefore, value of a and b are: 10 and 6