Question

Escape velocity of an atmospheric particle which is 1000km

Answer 1

Answer:

question poora Kar

Explanation:

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Answer 2

Answer:

Escape velocity on surface of earth is

v = sqrt(2GM / R) = 11.2 km/s ……[2]

Escape velocity at height h is

v’ = sqrt[2GM / (R + h)] ……[1]

Divide equations [1] and [2]

v / v’ = sqrt[(R + h) / R)]

11.2 / v’ = sqrt[(6400 + 1000) / 6400]

v’ = 11.2 / 1.075

v’ = 10.4 km/s

Escape velocity at that height is 10.4 km/s

Explanation:

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