Question

Escape velocity of mass on the surface of earth depends upon gravitational constant g mass of earth m and radius of earth are derive a relation connecting these physical quantities

Answer 1

Answer:v=k G^a M^b R^c

[M^0L^1T^-1] = K [M^b-a] [L^c+3a] [T^-2a]

solving it

M^0 = M^b-a

0 = b-a

a=b

similarly

1 = c + 3a

-1 = -2a

a = 1/2

b = 1/2

c = -1/2

therefore v = k root of GM/R

Explanation: