establish the relationship between the linear and angular velocity
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Answered by
0
Hint-
v=ds/dt
v=ds/dt
. What does this
s
s
represent(i.e. which 'path' is your object on)? We know angular velocity is the rate of change of angular displacement, i.e.
ω=dθ/dt
ω=dθ/dt
.What is the relation between
s
s
and
θ
θ
? Are they proportional? Plug in the known data in the first equation.
I believe this should be sufficient
v=ds/dt
v=ds/dt
. What does this
s
s
represent(i.e. which 'path' is your object on)? We know angular velocity is the rate of change of angular displacement, i.e.
ω=dθ/dt
ω=dθ/dt
.What is the relation between
s
s
and
θ
θ
? Are they proportional? Plug in the known data in the first equation.
I believe this should be sufficient
Answered by
1
Thus, for a given angular velocity ω, the linear velocity v of the particle is directly proportional to the distance of the particle from the centre of the circular path (i.e) for a body in a uniform circular motion,
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