Estimate the energy of a oscillator using hisenberg uncertainity principle
Answers
Answered by
1
ΔxΔp = h/2π
energy = p∧2/2m
so by uncertainity principle
energy = (h∧2)/8(π∧2)m(Δx∧2)
energy = p∧2/2m
so by uncertainity principle
energy = (h∧2)/8(π∧2)m(Δx∧2)
Similar questions