Chemistry, asked by amshuvadla, 7 months ago

Estimate the temperature at which the equilibrium pressure due to the dissociation of solid NH4Cl in a closed vessel is equal to one atmosphere. (In = = 0.25 = -1.39, In 0.50 = -0.69, In 0.75 =

-0.29)

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Answered by amritaprasad8b

Answer:

Explanation:volume are kept constant and more Cl2 (9) is added to an equilibrium mixture of these three ... in the vessel is doubled at constant temperature, k = pro → does not ... e) The partial pressure of CO2 in the vessel remains unchanged. Answer: ... the initial partial pressures are PA = 2.0 atm, Pg = 0.50 atm and Pc = 1.0 atm.

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Estimate the temperature at which the equilibrium pressure due to the dissociation of solid NH4Cl in a closed vessel is equal to one atmosphere. (In = = 0.25 = -1.39, In 0.50 = -0.69, In 0.75 =-0.29)​

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Estimate the temperature at which the equilibrium pressure due to the dissociation of solid NH4Cl in a closed vessel is equal to one atmosphere. (In = = 0.25 = -1.39, In 0.50 = -0.69, In 0.75 =

-0.29)