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A car travels from A to B and returns to its original position.
The distance between A and B is 2000 m.
(0) Find the total displacement of the car. ☺
(1) The car takes 5 min to travel from A to B but takes 8 min to travel back
from B to A. Is the speed of the caf greater while going from A to B or while
travelling back from B to A?
ill) When can the magnitude of distance and displacement be equal for a body
in motion?
Answers
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Explanation:
(1) DISPLACEMENT =DISTANCE BETWEEN START AND END POINT OF ANY BODY.
SO
TOTAL DISPLACEMENT OF CAR = 0
BECAUSE CAR RETURNED TO THE SAME PLACE
(2) SPEED OF CAR WHEN CAR GO FROM A TO B= DISTANCE(2000m)÷TIME(5min)
(S1) = 2000÷5×60
(S1) = 2000÷300
(S1) =20/3
(S1) =80/12
AND NOW SPEED OF CAR WHEN CAR RETURNED FROM B TO A (S2)
SPEED = DISTANCE÷TIME
(S2) =2000÷8×60
(S2) =2000/480
(S2) =25/12
THEREFORE WE FIND THAT SPEED OF CAR IS GREATER WHILE GOING FROM A TO B.
(3) THE MAGNITUDE OF SPEED AND DISPLACEMENT BE EQUAL FOR A BODY IN MOTION WHEN BODY MOVES IN A STRAIGHT PATH IN ONE DIRECTION.
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