Ethanoic acid reacts with a compound X to form a sweet smelling substance Y.X on being strongly heated looses water molecule and form a unsaturated compound Z.Identify X,Y,Z and give the reaction involved
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X= Ethanol
Y = Ethyl Ethnoate
Z = Ethene
Ch3Cooh + C2H5OH ----->
Ch3Coo.C2H5 + H2O
C2H5OH --------> CH2==H2C (IN PRESENCE OF H2SO4 AT 443K)
Y = Ethyl Ethnoate
Z = Ethene
Ch3Cooh + C2H5OH ----->
Ch3Coo.C2H5 + H2O
C2H5OH --------> CH2==H2C (IN PRESENCE OF H2SO4 AT 443K)
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1
X is Ethanol.
Y is Ethyl ethanoate.
Z is Ethene.
CH3COOH + CH3CH2OH → CH3COOCH2CH3 + H2O
CH3CH2OH (∆ AT 443 K) → CH2CH2 + H2O
Y is Ethyl ethanoate.
Z is Ethene.
CH3COOH + CH3CH2OH → CH3COOCH2CH3 + H2O
CH3CH2OH (∆ AT 443 K) → CH2CH2 + H2O
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