Chemistry, asked by syednadim8522, 2 months ago

Ethanol in presence of sodium wire yields​

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Answered by CyberSquad
1

Answer:

f a small piece of sodium is dropped into ethanol, it reacts steadily to give off bubbles of hydrogen gas and leaves a colorless solution of sodium ethoxide:  CH3CH2ONa . The anion component is an alkoxide.

2CH3CH2OH(l)+2Na(s)→2CH3CH2O−(aq)+2Na+(aq)+H2(g)(1)

If the solution is evaporated carefully to dryness, then sodium ethoxide ( CH3CH2ONa ) is left behind as a white solid. Although initially this appears as something new and complicated, in fact, it is exactly the same (apart from being a more gentle reaction) as the reaction between sodium and water - something you have probably known about for years.

2H2O(l)+2Na(s)→2OH−(aq)+2Na+(aq)+H2(g)(2)

If the solution is evaporated carefully to dryness, then the sodium hydroxide ( NaOH ) is left behind as a white solid.

We normally, of course, write the sodium hydroxide formed as  NaOH  rather than  HONa  - but that's the only difference. Sodium ethoxide is just like sodium hydroxide, except that the hydrogen has been replaced by an ethyl group. Sodium hydroxide contains  OH−  ions; sodium ethoxide contains  CH3CH2O−  ions.

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Answered by krantibakoriya81
0

Answer:

/Bookshelves/Organic_Chemistry/Supplemental_Modules_(Organic_Chemistry)/Alcohols/Reactivity_of_Alcohols/The_Reaction_Between_Alcohols_and_Sodium

The Reaction Between Alcohols and Sodium - Chemistry ...

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