Question

ethanol is degraded in the liver by a series of redox reactions. calculate the three oxidation states/numbers of each of the indicated functional group atom in the following reaction CH3-CH2-OH -> CH3-C=O-H -> CH3C=O-O-H please help

Answer 1

Answer:

hello dear,

Explanation:

Now methyl carbon has three hydrogens so (3*1=3), so oxidation number of methyl carbon is -3 as to nullify the overall charge. Oxygen in alcohol has -2 oxidation number but as hydrogen is attached with it (-OH group) the net oxidation number on oxygen is -1. The carbon has to H atoms attached to it so net (2*1=2).

i hope it helps u