Ether boils at 33.5'C at 1atm pressure . At what temperature It will boils when the temperature is 750mm, given that the heat of vapourisation of ether in 369.86 j per gram ?
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(ln 750 mm)/(76 mm) = (369.86 J g ^(-1) xx74 g mol ^(-1))/( 8. 314 J K ^(-1) mol ^(-1)) (( T _(2) - 306.5 K)/(306.5 K ))
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T _(2) = 305. 9 k
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implies k = 2 b ar m ^(-1) implies ( p _(2) )/( p _(1)) = (d _(2))/(d _(1)) implies d_(2) = d _(1) (( p _(2))/( p _(1))) = 0. 5 xx 5 = 2. 5 m
<br> Also,
-dW = p dV, V = (4)/(3) pi ((d)/(2)) ^(3) = (4)/(3) pi (d ^(3))/( 8) = (pi)/(6) d ^(3)
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implies dV = (pi)/(6) 3d ^(2)d d = (pi)/(2) d ^(2) d d implies - dW = kd xx (pi)/(2) d ^(2) d d = (k)/(2) pi d ^(3) d d
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implies - W = int -dW = (k)/(2) pi int _( d _(1)) ^( d _(2))d ^(3) dd = (k pi)/( 2) [ (d ^(2))/( 4) ] _( d _(1)) ^(d _(2)) = (kpi )/( 8) (d _(2) ^(4) - d _(1) ^(4))
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