Evaluate ʃ₀ᵌ ʃ₁² xy (1+x+y)dxdy
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3
Answer:
26.25
Step-by-step explanation:
I = ʃ₀ᵌ ʃ₁² xy (1+x+y)dxdy
I = ʃ₀ᵌ ʃ₁² x (y+xy+y²)dxdy
I = ʃ₀ᵌ xdx ʃ₁²(y+xy+y²)dy
I = ʃ₀ᵌ xdx (y²/2+xy²/2+y³/3)
I = ʃ₀ᵌ xdx {(4/2+4x/2+8/3) - (x + 5/6)}
I = ʃ₀ᵌ x ( x + 23/6)dx
I = ʃ₀ᵌ ( x ² + 23/6x)dx
I= x³/3 + 23x²/12
I= 3² + 23x9/12
I= 9 + 69/4
I = 26.25
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