Question

Evaluate :  ∞ − 0 2 e sin3tdt t .​

Answer 1

Answer:

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Answer 2

Answer:

Laplace transform of ∫∞0e−tsin2ttdt

Laplace transform of ∫∞0e−tsin2ttdt.

So far I've calculated that e−tsin2tt transformed equals 18(ln((s+1)2+4)−2ln(s+1)).

Step-by-step explanation:

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