Math, asked by palashgiri42, 4 months ago

Evaluate (1.01)³ using suitable identity.

Answers

Answered by navdeepkaur240306

2

Answer:

(1.01) × (1.01)

=(1.01)^2

=(1+0.01) ^ 2

=(1)^2+(0.01)^2+2(1)(0.01)

=1 +0.0001 + 0.02

=1.0201

Step-by-step explanation:

thank you ❤️...

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