Question

evaluate :
1) (29^0-23^0)×16^0
2) (-2)^3×5-4-11
3) (-17)^0

Answer 1

1)29^0-23^0×16^0
n^0=1
(1-1)×1
0

2)-2³×5-4-11
-8×5-15
-40-15
=-55

3)-17^0
n^0=1
1
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Answer 2

1) (29^0-23^0)×16^0
= (1-1)×16^0
=0 ×16^0
= 0

2) (-2)^3×5-4-11
=(-8)×5-4-11
= (-40)-4-11
= (-40)-15
= -55

3) (-17)^0
= 1