Question

Evaluate
1/3+4sinx dx​

Answer 1

Step-by-step explanation:

$\frac{1}{3 + 4sinx} dx$

By using chain rule

$\frac{dy}{dx} = \frac{3 + 4sinx \frac{dy}{dx}1 - (3 + 4sinx) }{ {(3 + 4sinx)}^{2} }$

$\frac{dy}{dx} = \frac{(3 + 4sinx \times 0 - 3 - 4sinx)}{ {(3 + 4sinx)}^{2} }$

$\frac{dy}{dx} = \frac{ - 3 - 4sinx}{ {(3 + 4sinx)}^{2} } is \: the \: answer \: of \: this \: question$