Math, asked by grroadways, 8 months ago

evaluate
(1/6)^-1+(1/7)^-1+(1/8)^-1​

Answers

Answered by ramtej5691
0

Answer:

21

Step-by-step explanation:

since a^-1=1/a

(1/a)^-1 = a

i.e. (1/6)^-1 + (1/7)^-1 + (1/8)^-1 =

6+7+8 = 21

Answered by niharika359285
2

Step-by-step explanation:

We know that any fraction to the power -1 becomes reciprocal...

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