evaluate
(1/6)^-1+(1/7)^-1+(1/8)^-1
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Answered by
0
Answer:
21
Step-by-step explanation:
since a^-1=1/a
(1/a)^-1 = a
i.e. (1/6)^-1 + (1/7)^-1 + (1/8)^-1 =
6+7+8 = 21
Answered by
2
Step-by-step explanation:
We know that any fraction to the power -1 becomes reciprocal...
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