Math, asked by jraheja310, 4 months ago

evaluate 1-tan^230°/1+cot^230°​

Answers

Answered by jitendra12iitg
0

Answer:

The answer is \dfrac{1}{6}

Step-by-step explanation:

  • Since \tan30^\circ=\dfrac{1}{\sqrt 3} and \cot30^\circ=\sqrt 3

Therefore

                 \dfrac{1-\tan^230^\circ}{1+\cot^230^\circ}=\dfrac{1-(\dfrac{1}{\sqrt 3})^2}{1+(\sqrt 3)^2}\\=\dfrac{1-\dfrac{1}{3}}{1+3}=\dfrac{\dfrac{2}{3}}{4}=\dfrac{1}{6}

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