evaluate 1-tanA/1-cotA =tan2A
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Answer:
(1-tanA)square / (1-cotA) square
(1-tanA) square / [(tanA - 1)/ tanA)] square
(1-tanA) square / [(tanA - 1)sq / tan sq A]
(1-tanA)sq / [(1-tanA) sq / tan sq A]
Tan sq A
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Answered by
2
Answer:
(1-tanA)square / (1-cotA) square
(1-tanA) square / [(tanA - 1)/ tanA)] square
(1-tanA) square / [(tanA - 1)sq / tan sq A]
(1-tanA)sq / [(1-tanA) sq / tan sq A]
Tan sq A
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