Question

evaluate (101)² by using suitable identity​

Answer 1

Step-by-step explanation:

$= {(101)}^{2} </p><p>By using (a+b)^2</p><p> = {(100 + 1)}^{2}$

$= {100}^{2} + {1}^{2} + 200 \\ = 10000 + 1 + 200 \\ = 10201$

Answer 2

Step-by-step explanation:

We will use an identity

( a + b ) ^ 2 = a ^ 2 + b ^ 2 + 2ab

Given,

( 101 ) ^ 2

If we split the given value correctly then,

( 100 + 1 ) ^ 2

Now,

a = 100 and b = 1

Therefore,

( 101 ) ^ 2 = ( 100 ) ^ 2 + ( 1 ) ^ 2 + 2 * 100 * 1

( 101 ) ^ 2 = 10000 + 1 + 200

On performing simple addition we get,

( 101 ) ^ 2 = 10,201

Therefore,

Your answer is 10201