Math, asked by kavyasingh88, 10 months ago

Evaluate 101 x 99 using appropriate identities​

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Answered by Aashee9
5

Answer:

=101×99

=(100+1)(100-1)

using Identity (a+b)(a-b)=a^2-b^2

=100^2-1^2

=10000-1

=9999

Answered by kirtaniaskk
3

Hi mate!!!!!!!!!

101 x 99

(101 + 1) (101 - 1)

By using the propriety (a+b)(a-b)=a^2 - b^2

(100)^2 - 1

10000 - 1

9999

Hope this will help you.

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