Math, asked by hooo3, 1 year ago

evaluate: (105)^2-(104)^2 / (6)^2-(5)^2

Answers

Answered by Navasaan
7
using a^2-b^2=(a+b)(a-b)
=(105+104)(105-104)/(6+5)(6-5)
=209*1/11*1
=19
Answered by VasuGupta23
16
 {105}^{2} - {104}^{2} \div {6}^{2} - {5}^{2} \\ = (105 + 104)(105 - 104) \div( 6 + 5)(6 - 5) \\ = 209 \times 1 \div 11 \times 1 \\= \frac{209}{11} \\ =19
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