Question

Evaluate 10m +\dfrac {n^2}410m+ 4 n 2 ​ when m=5m=5 and n=4n=4.

Answer 1

Answer:

Step-by-step explanation:

$10m+\frac{n^{2}}{410m + 4n^{2}}$

Given : m=5, n=4

Substituting the values of m and n in the expression we have

$10(5)+\frac{4^{2}}{410(5) + 4(4)^{2}}\\\\= 50 + \frac{16}{410(5) + 4(4^{2})}\\\\= 50 + \frac{16}{2114}\\\\= 50 + \frac{8}{1057}\\\\= \frac{(50*1057)+8}{1057}\\\\=\frac{52858}{1057}$

∴ The answer is $\frac{52858}{1057}$

Answer 2

HELLO DEAR,



GIVEN:- m = 5 & n = 4



now, 10m + $\dfrac {n^2}410m+ 4n^2$

=> 10(5) + 4²/4*10(5) + 4(4)²

=> 50 + 4(50) + 64

=> 50 + 200 + 64

=> 314



I HOPE IT'S HELP YOU DEAR,
THANKS